Push-Pull Class E Circuit

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Push-Pull Class E Circuit

Postby NE4AM » Fri Mar 11, 2005 11:04 pm

A simple circuit having many benifits can be found at:
http://www.freepatentsonline.com/5327337.html

Enjoy!
73 - NE4AM
73 - Dave NE4AM
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Nice circuit

Postby N9NEO » Fri Apr 08, 2005 1:22 am

Nice job Dave. You are a Pioneer!

Good site too! I was able to download nice schematic to go with text.

I will try tuning up my rig like you have done. I am using the Cal tech inverse F tune up specs now. I am not so sure of best way to tune harmonic filter.

73
Bob
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Push Pull Class E

Postby wa4daw/Jim » Fri Apr 08, 2005 8:13 am

Great info Dave

I have had an interest in Push Pull Class E for some time and this info is just what I was looking for. Just for kicks, I put the formulas in a spread sheet and played with the numbers, finding that there is a combination that will allow 40 meter operation using 2 FQA11N90's with no additional parallel capacitance for class E operation. Well, I threw the circuit together on the bench and it works giving a very good class e wave shape at about 135 watts input. Other calculations show this can also be done on 80 meters but I have not tried it.
Now all I have to do is finish my modulator and I'll see you on 40.

73
Jim
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Postby frank carcia » Mon Apr 11, 2005 3:15 pm

YEA another convert! gfz
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Postby frank carcia » Tue Apr 12, 2005 9:46 am

I ran the numbers against both of my rigs and learned :
160 meter rig I need more shunt C
75 meter rig I can go to a lower Q in the output circuit and my shunt C
agrees with the formula.
This is the best push pull data I've seen so far.
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Postby NE4AM » Wed Apr 20, 2005 2:22 pm

I just looked at the patent - there is an error in the formula for calculating the shunt C. There should be a term to take into account the output transformer turns ratio squared. Not an issue if the transformer is 1:1.

(The patent was filed and issued after I was no longer with the company, so I'm not responsible for its content!)

73 - Dave
73 - Dave NE4AM
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Postby VK3KRI » Thu Apr 21, 2005 5:54 am

NE4AM wrote:I just looked at the patent - there is an error in the formula for calculating the shunt C. There should be a term to take into account the output transformer turns ratio squared. Not an issue if the transformer is 1:1.

(The patent was filed and issued after I was no longer with the company, so I'm not responsible for its content!)

73 - Dave


I think That n & m in the equation for R1 are transposed as well
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Postby frank carcia » Thu Apr 21, 2005 6:54 am

Look at the R1 formula that accounts for transformer ratio. R1 is used as a term to find C1. fc
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